# Chem Assignment

Consider the following equations. 3 A + 6 B → 3 D, ΔH = -440. kJ/mol…

3 A + 6 B → 3 D, Δ*H* = -440. kJ/mol

E + 2 F → A, Δ*H* = -102.5 kJ/mol

C → E + 3 D, Δ*H* = +64.5 kJ/mol

Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction?

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